Step-by-step explanation:
[tex]x=3\\y=\frac{1}{3}\\z=5\\ \\\frac{12x-3y}{4x-z} \\=\frac{12*3-3*\frac{1}{3} }{4*3-5}\\=\frac{36-\frac{3}{1}*\frac{1}{3} }{12-5} \\=\frac{36-\frac{3}{3}}{7}\\=\frac{36-1}{7}\\=\frac{35}{7}\\=5[/tex]
Answer:
the answer is 5
