Answer:
1.05 X 180 = 189 gm of dextrose
Explanation:
What mass in grams of dextrose (C 6 H 12 O 6) will be required to produce 3.00 L of a 0.35 M aqueous solution
the molar mass of (C 6 H 12 O 6) is
(6 X 12) + (1 X 12) + (6 x 16) =
72 +12 + 96=
180 g/mol
we need 3 L x 0.35 moles/L = 1.05 moles of dextrose
so
1.05 X 180 = 189 gm of dextrose
