Answer:
[tex]x_1\approx0.79,x_2\approx-3.79[/tex]
Step-by-step explanation:
[tex]x^2+3x=3[/tex]
[tex]x^2+3x-3=0[/tex]
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]x=\frac{-3\pm\sqrt{(-3)^2-4(1)(-3)}}{2(1)}[/tex]
[tex]x=\frac{-3\pm\sqrt{9+12}}{2}[/tex]
[tex]x=\frac{-3\pm\sqrt{21}}{2}[/tex]
[tex]x_1\approx0.79,x_2\approx-3.79[/tex]
