A z score of 0.97 corresponds with a probability of 83.40%
The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean,\sigma=standard\ deviation[/tex]
From the normal distribution table:
P(z < 0.97) = 0.8340 = 83.40%
A z score of 0.97 corresponds with a probability of 83.40%
Find out more on z score at: https://brainly.com/question/25638875
