Respuesta :
[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &3.6\\ t=\textit{elapsed time}\dotfill &45\\ h=\textit{half-life}\dotfill &14.4 \end{cases} \\\\\\ A=3.6\left( \frac{1}{2} \right)^{\frac{45}{14.4}}\implies A=3.6\left( \frac{1}{2} \right)^{3.125}\implies A\approx 0.41265[/tex]
Answer: 0.41
Step-by-step explanation:
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