Answer:
C) [tex]\theta=\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}[/tex]
Step-by-step explanation:
[tex]sin^2\theta=\frac{1}{2},\: 0\leq\theta\leq2\pi\\ \\\frac{1-cos(2\theta)}{2}=\frac{1}{2}\\ \\1-cos(2\theta)=1\\\\cos(2\theta)=0\\\\2\theta=\frac{\pi}{2}+\pi n\\ \\\theta=\frac{\pi}{4}+\frac{\pi}{2}n\\ \\ \theta=\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}[/tex]
Recall the identity [tex]sin^2\theta=\frac{1-cos(2\theta)}{2}[/tex]
