Answer: 4, 5
Step-by-step explanation:
The domain restrictions are [tex]x \neq 1[/tex] and [tex]x \neq -3[/tex] since those are the values of x for which the denominators equal 0.
To solve, we can start by cross multiplying:
[tex](x+3)(x+2)=7(2x-2)\\x^{2}+5x+6=14x-14\\x^{2}-9x+20=0\\(x-4)(x-5)=0\\x=4, 5[/tex]
