Respuesta :

fieryanswererft

Answer:

missing length: 3

solving similarities:

[tex]\sf \frac{YK}{YM} = \frac{TN}{NM}[/tex]

[tex]\sf \frac{2}{1} = \frac{6}{?}[/tex]

[tex]\sf ? = \frac{6*1}{2}[/tex]

[tex]\sf ? = \frac{6}{2}[/tex]

[tex]\sf ? = 3[/tex]

NM be x

[tex]\\ \rm\hookrightarrow \dfrac{x}{6}=1/2[/tex]

[tex]\\ \rm\hookrightarrow 2x=6[/tex]

[tex]\\ \rm\hookrightarrow x=6/2[/tex]

[tex]\\ \rm\hookrightarrow x=3[/tex]

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