Answer:
[tex] \frac{ {r}^{ 3} + 25}{p(q + r)^{4} } = \frac{ {(3.5)}^{3} + 25}{5(6 + 3.5)^{4} } = \frac{42.875 + 25}{5 {(9.5)^{4} }} \\ \\ = \frac{67.875}{5(8145.0625)} = \frac{67.875}{40725.3125} \\ \\ = 0.00166665 = 0.002[/tex]
Step-by-step explanation:
(3.5^3 +25) ÷5(6+3.5)^4
(42.875 + 25) ÷5 (9.5)^4
(67.875) ÷ 5 (8145.0625)
(67.875) ÷ 203626.5625
=0.00033333078)
