Answer: C
Step-by-step explanation:
To Ax^2+Bx+C=0 form (add 2 to both sides):
[tex]2y^2-5y+2=0[/tex]
Use the quadratic formula (a = 2, b=-5, c= 2)
[tex]y=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\cdot \:2}}{2\cdot \:2}[/tex]
[tex]y=\frac{-\left(-5\right)\pm \:3}{2\cdot \:2}[/tex]
[tex]y=\frac{-\left(-5\right)+3}{2\cdot \:2},\:y_2=\frac{-\left(-5\right)-3}{2\cdot \:2}[/tex]
[tex]y_{1}=2,\:\\y_{2}=\frac{1}{2}[/tex]
