Answer:
[tex]\sf y=7\frac{2}{3}[/tex] and [tex]\sf x = \frac{2}{3}[/tex]
Explanation:
[tex]\sf (1) \ \ (2x+y = 9)[/tex]
[tex]\sf (1) \ \ (2x+5y = 37)[/tex]
solve for y:
[tex]\sf 2x + y = 9[/tex]
[tex]\sf 2x + 5y = 37[/tex]
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[tex]\sf 0x + 6y = 46[/tex]
[tex]\sf 6y = 46[/tex]
[tex]\sf y=\frac{23}{3}[/tex]
[tex]\sf y=7\frac{2}{3}[/tex]
solve for x:
[tex]\sf 2x + y = 9[/tex]
[tex]\sf 2x = 9 - y[/tex]
[tex]\sf 2x = 9 - \frac{23}{3}[/tex]
[tex]\sf 2x = \frac{4}{3}[/tex]
[tex]\sf x = \frac{2}{3}[/tex]
