[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Here's the solution ~
[tex]\qquad \sf \dashrightarrow \:b(b + 12) = 0[/tex]
Here, we have two cases :
Case 1
[tex]\qquad \sf \dashrightarrow \:b = 0[/tex]
Case 2
[tex]\qquad \sf \dashrightarrow \:b + 12 = 0[/tex]
[tex]\qquad \sf \dashrightarrow \:b = - 12[/tex]
Hence, 0 and -12 are the only possible solutions for given equation.
