Answer:
-120-x
Step-by-step explanation:
Given:
[tex]\displaystyle \large{|120+x| \quad (x < -120)}[/tex]
This is the same as previous one. Recall modulus property:
[tex]\displaystyle \large{|a+x| = \begin{cases} a+x \quad (x \geq -a) \\ -a-x \quad (x < -a) \end{cases}}[/tex]
Keep in mind that |x+a| and |a+x| are equal via addition property.
Since the question gives interval of x < -120:
Therefore, the expression is -120-x
