Respuesta :

ingramjazmine9

Answer:

So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.

Explanation:

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[tex]\\ \rm\Rrightarrow r=0.529\dfrac{n^2}{Z^2}[/tex]

  • For hydrogen Z=1

[tex]\\ \rm\Rrightarrow r=0.529(5)²[/tex]

[tex]\\ \rm\Rrightarrow r=0.529(25)[/tex]

[tex]\\ \rm\Rrightarrow r=1.3225nm[/tex]