Answer: (6, -5)
Reason:
Rewrite the given equation into [tex](x-6)^2 + (y-(-5))^2 = 5^2[/tex]
I changed the y+5 into y-(-5), and also replaced 25 with [tex]5^2[/tex]
Then compare that to the circle template of [tex](x-h)^2 + (y-k)^2 = r^2[/tex]
We see that h = 6 and k = -5 to give a center of (h,k) = (6, -5)
Side note: the radius is r = 5 units
