bigscarletfamily bigscarletfamily
  • 01-08-2022
  • Mathematics
contestada

\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}

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ZeeSq
ZeeSq ZeeSq
  • 01-08-2022

Answer:

[tex]\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}[/tex]

=

[tex]\frac{ \sqrt{2} }{a + b} [/tex]

Step-by-step explanation:

[tex]\left(a-b\right)\sqrt{\frac{2}{a^2-b^2}}[/tex]

[tex](a - b)( \frac{ {2}^{ \frac{1}{2} } }{(a + b)(a - b)} )[/tex]

[tex] \frac{(a - b)( {2}^{ \frac{1}{2} }) }{(a - b)(a + b)} = \frac{ \sqrt{2} }{a + b} [/tex]

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