The explicit formula is Tn = 18[[tex]\frac{2}{3} ^{n-1}[/tex]]
here, we have to find n.
Now, F(2) = 2/3 * f1 = 2/3 * 18 = 12
F(3) = 2/3 * f(2) = 2/3 * 12 = 8
F(4) = 2/3 * F(3) = 2/3 * 8 = 16/3
F(5) = 2/3 * 16/3 = 32/9
These equations form a pattern.
That is Tn = (2/3)^(n-1)(18)
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