Answer:
[tex]x=1+\sqrt[n]{y}[/tex]
Step-by-step explanation:
Since: [tex](x-1)*(x-1)*(x-1)=y[/tex]
that would imply: [tex](x-1)=\sqrt[3]{y}[/tex]
This is a bit more clear, if you write the equation as:
[tex](x-1)^3=y[/tex]
and then take the cube root of both sides
[tex]\sqrt[3]{(x-1)^3}=\sqrt[3]{y}[/tex]
Which simplifies to
[tex]x-1=\sqrt[3]{y}[/tex]
Now add 1 to both sides, and you get the equation:
[tex]x=1+\sqrt[n]{y}[/tex]
