Explanation:
To solve this question, we need to know the Avogadro's constant:
6.022 x 10^23 atoms equal 1 mol.
So, in this case we have 3.01x10^23
We first transform it to moles and then to grams, using the following formula:
m = n*MM
where:
m = mass
n = moles
MM = molar mass of silver nitrate (AgNO3) = 169.87 g/mol
6.022 x 10^23 ---- 1 mol
3.01x10^23 ---- x mol
x = 0.5 moles
m = 0.5 * 169.87 g/mol
m = 85 g
Answer: 85 g
