The given height is:
[tex]\begin{gathered} h=5\frac{1}{2}in \\ h=\frac{11}{2}in \end{gathered}[/tex]And the base is 5 in:
So the area of parallelogram is:
[tex]\begin{gathered} A=b\times h \\ A=5\times\frac{11}{2} \\ A=\frac{55}{2}sq\text{ in} \end{gathered}[/tex]So the area of the parallelogram is 55/2 sq inches.
