[tex]\begin{gathered} Calculate\text{ the blocks for }BE, \\ \sin 65^{\circ}=\frac{BD}{BE} \\ \sin 65^{\circ}=\frac{7}{BE} \\ BE=7.7\text{ blocks} \\ \text{Now, calculate the blocks for AE, } \\ sin65^{\circ}=\frac{AC}{AE} \\ \sin 65^{\circ}=\frac{10}{AE} \\ AE=11 \\ So,\text{ the BA} \\ BA=AE-BE \\ BA=11-7.7 \\ BA=3.3\text{ blocks} \end{gathered}[/tex]
