The sum of three consecutive integers is less than 186
Let "n" represent the first integer.
Then the second integer can be represented as "n+1"
And the second integer as "n+2"
Their sum can be expressed as:
[tex]n+(n+1)+(n+2)<186[/tex]From this inequality you can determine the value of n
[tex]\begin{gathered} n+n+1+n+2<186 \\ 3n+3<186 \\ 3n<186-3 \\ 3n<183 \\ \frac{3n}{3}<\frac{183}{3} \\ n<61 \end{gathered}[/tex]Tha maximum value of the first integer is 61
