Given
[tex]y+3=\frac{1}{3}(x-5)[/tex]
To graph the above line.
Explanation:
It is given that,
[tex]y+3=\frac{1}{3}(x-5)[/tex]
That implies,
[tex]\begin{gathered} 3(y+3)=x-5 \\ 3y+9=x-5 \\ x-3y-5-9=0 \\ x-3y-14=0 \end{gathered}[/tex]
Then,
Hence, the graph of the above line is plotted as,
