Respuesta :

wer:

Step-by-step explanation:

Radicals properties:

[tex]x^{-a}=\frac{1}{x^a}[/tex][tex]x^{\frac{m}{n}}=\sqrt[n]{x^m}[/tex]

In this question:

[tex]\frac{1}{x^{\frac{-3}{6}}}=x^{-(-\frac{3}{6})}=x^{\frac{3}{6}}=x^{\frac{1}{2}}=\sqrt[]{x}^{}[/tex]