Given the inequality
[tex]5(7x+9)\leq6x-2[/tex][tex]\begin{gathered} 5\cdot7x+5\cdot9\leq6x-2 \\ 35x+45\leq6x-2 \\ 35x-6x\leq-2-45 \\ 29x\leq-47 \\ x\leq-\frac{47}{29} \end{gathered}[/tex]So, the solution of the inequality is the interval ( -∞ , -47/29]
