The tangent function is given by:
[tex]\tan (\theta)=\frac{opposite}{_{\text{ }}adjacent}=\frac{5}{12}[/tex]
Since the angle is in the 3rd quadrant the opposite side and the adjacent side are negative. So, the cotangent function is given by:
[tex]\cot (\theta)=\frac{1}{\tan (\theta)}=\frac{adjacent}{_{\text{ }}opposite}=\frac{-12}{-5}=\frac{12}{5}[/tex]
Answer:
12/5
