The boundary line is 2x+2y=-6.
The inequality can be either of th etwo,
[tex]2x+2y\leq-6,2x+2y\ge-6[/tex]
Since the portion contaims (0,0).
Putting it in both the inequality ,
we have,
[tex]2\times0+2\times0\leq-6\Rightarrow0\leq-6[/tex]
This is not possible . So we reject the first inequality.
Again,
[tex]2\times0+2\times0\ge-6\Rightarrow0\ge-6[/tex]
This is possible.
Thus the required inequality is,
[tex]2x+2y\ge-6[/tex]
