The rule of the surface area of a box whose dimensions are L, W, and H is
[tex]S.A=2(L\times W+L\times H+W\times H)[/tex]
Since the dimensions of the sugar box are 10 cm, 5 cm ,and 16 cm, then
L = 10
W = 5
H = 16
Substitute them in the rule above
[tex]\begin{gathered} S.A=2(10\times5+10\times16+5\times16) \\ \\ S.A=2(50+160+80) \\ \\ S.A=2(290) \\ \\ S.A=580\text{ cm}^2 \end{gathered}[/tex]
The surface area is 580 square cm
