Given expression is
[tex](x^3+\frac{2}{x})^8[/tex]This is of the form
[tex](a+b)^n[/tex][tex]\text{where}a=x^3,\text{ b=}\frac{2}{x}\text{ and n=8}[/tex]Recall that
[tex]In\text{ the binomial expansion of }(a+b)^n,\text{ there are total n+1 terms.}[/tex]Here n=8.
[tex]In\text{ the binomial expansion of }(x^3+\frac{2}{x})^8,\text{ there are total 8+1=9 terms.}[/tex]Hence option A is correct.
