Solution (12):
Given the triangle;
The opposite side is labelled as x and the adjacent side is 17.
Using the tangent trigonometry ratio, we have;
[tex]\tan\theta=\frac{opposite}{adjacent}[/tex]
Thus;
[tex]\begin{gathered} \tan(51^o)=\frac{x}{17} \\ \\ x=17\tan(51^o) \\ \\ x=20.99 \\ \\ x\approx21 \end{gathered}[/tex]
