To determine the required slope intercept form, take the heartbeat as varible y and time as varible x.
Now select any two coordinates from the table.
Take (2,3) and (4,6).
Use the two point form,
[tex]\begin{gathered} \frac{y-3}{x-2}=\frac{6-3}{4-2} \\ 2(y-3)=3(x-2) \\ 2y-6=3x-6 \\ 2y=3x \\ y=\frac{3}{2}x \end{gathered}[/tex]
Thus, y=1.5x is the requried form of the line.
