Respuesta :

we get that

[tex]h_b=\frac{88}{4\cdot\pi}\approx7[/tex]

as the figure are congruent we get

[tex]h_a=\frac{5}{2}\cdot7=17.5[/tex]

so the volume is

[tex]V_a=\pi\cdot5^2\cdot17.5=1375ft^3[/tex]

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