Using the formula below
[tex]\begin{gathered} b^2-4ac \\ \text{Solving for the first option} \end{gathered}[/tex]
For 2x²+4x+4, relataing it to the general form of a quadratic equation,
[tex]ax^2+bx+2=0[/tex]
Where a, b, and c for the 2x²+4x+4 is given below,
[tex]\begin{gathered} a=2,b=4,c=4 \\ b^2-4ac=4^2-4(2\times4)=16-32=-16 \end{gathered}[/tex]
Since b²-4ac is not supposed to be negative (i.e complex roots),
Answer is A
