Given
The equation,
[tex]2b^2-18=-9b[/tex]
To solve for b.
Explanation:
It is given that,
[tex]2b^2-18=-9b[/tex]
That implies,
[tex]\begin{gathered} 2b^2-18=-9b \\ 2b^2+9b-18=0 \\ 2b^2-3b+12b-18=0 \\ b(2b-3)+6(2b-3)=0 \\ (2b-3)(b+6)=0 \\ 2b-3=0,b+6=0 \\ 2b=3,b=-6 \\ b=\frac{3}{2},b=-6 \end{gathered}[/tex]
Hence, the answer is 3/2, -6.
