Respuesta :

[tex]\sqrt[3]{9}\text{ }\cdot\sqrt[3]{-24}\text{ =}\sqrt[3]{(9)\cdot(-24)}=\sqrt[3]{-216}[/tex][tex]\sqrt[3]{-216}\text{ = }\sqrt[3]{(-6)^3}[/tex]

we can easily calculate that -6 times -6 times- 6 =- 216 it is why we can do this equality

because we have an exponent 3 and a cubic root we can cancel both so the answer of

[tex]\sqrt[3]{9}\text{ }\cdot\sqrt[3]{-24}=\text{ -6}[/tex]

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