Answer:
[tex]\theta=\frac{2\pi}{3}+\pi\cdot n[/tex]
Step-by-step explanation:
Find the general solution for:
[tex]\begin{gathered} 3\cot \theta=-\sqrt[]{3} \\ \text{ Divide both sides by 3} \\ \cot \theta=-\frac{\sqrt[]{3}}{3} \end{gathered}[/tex]
Now, for the general solution, it is known that for
[tex]\begin{gathered} \cot (\frac{\pi}{6})=\sqrt[]{3} \\ \text{Then,} \\ \theta=\frac{2\pi}{3}+\pi\cdot n \end{gathered}[/tex]
