Given
[tex]f(x)=8x^2(x-9)(x+5)^2[/tex]
To find the zeros of multiplicity one, multiplicity 2, multiplicity 3.
Now,
The zeros of multiplicity 1 are,
[tex]\begin{gathered} x-9=0 \\ x=9 \end{gathered}[/tex]
The zeros of multiplicity 2 are,
[tex]\begin{gathered} x=0 \\ x+5=0 \\ x=-5 \end{gathered}[/tex]
There are no zeros of multiplicity three since the polynomial has no factor to the power 3.
