EXPLANATION:
In the exercise we have to perform the sum of two improper fractions which are heterogeneous because they have different denominators.
The procedure is the next:
[tex]\begin{gathered} \frac{2}{12}\text{ }+\frac{2}{4};=\frac{8+24}{48}=\frac{32}{48};\text{here }we\text{ simplify} \\ \\ \frac{32}{48}=\frac{16}{24}=\frac{8}{12}=\frac{4}{6}=\textcolor{#FF7968}{\frac{2}{3}} \\ \text{the answer is }\frac{2}{3} \end{gathered}[/tex]