The given expression is:
[tex]h=td^2[/tex]
Therefore,
[tex]td^2=h[/tex]
Dividing both sides of the equation by t:
[tex]\frac{td^2}{t}=\frac{h}{t}[/tex]
Hence,
[tex]d^2=\frac{h}{t}[/tex]
Thus,
[tex]d=\sqrt{\frac{h}{t}}=\frac{\sqrt{h}}{\sqrt{t}}[/tex]
To rationalize the equation by √t:
[tex]\begin{gathered} d=\frac{\sqrt{h}}{\sqrt{t}}\times\frac{\sqrt{t}}{\sqrt{t}}=\frac{\sqrt{ht}}{t} \\ d=\frac{\sqrt{ht}}{t} \end{gathered}[/tex]
d =
