The area of a parallelogram is given by the equation:
[tex]A=b\times h[/tex]
Where b is the base of the parallelogram and h is the height.
In this case, b=1/2 in and h=8in, then:
[tex]\begin{gathered} A=(\frac{1}{2}in)(8in) \\ =4in^2 \end{gathered}[/tex]
Therefore, the area of the described parallelogram, is:
[tex]4in^2[/tex]
