JoelizQ48791 JoelizQ48791
  • 03-11-2022
  • Mathematics
contestada

-20k - 5) + 2k = 5k + 5A k = 0B) k = 4k = 1D) k = 2

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ValiyahB579201 ValiyahB579201
  • 03-11-2022

The equation is:

[tex]\begin{gathered} -2(k-5)+2k=5k+5 \\ \end{gathered}[/tex]

We can distribute the -2 into the parenthesis

[tex]\begin{gathered} -2k+10+2k=5k+5 \\ 10=5k+5 \\ \end{gathered}[/tex]

now we solve for k

[tex]\begin{gathered} 10-5=5k \\ 5=5k \\ \frac{5}{5}=k \\ 1=k \end{gathered}[/tex]

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