Problem
[tex]\log ^1_7\text{ . }\log ^{25}_5[/tex][tex]\begin{gathered} =\text{ }\log ^{1\text{ }}_7\text{ x }\log ^{5^2}_5 \\ =\text{ }\log ^1_7\text{ x 2}\log ^5_5 \\ \log ^1_7\text{ = 0 and }\log ^5_5\text{ = 1} \\ =\text{ 0 }\times\text{ 2 }\times\text{ 1} \\ \text{= 0} \end{gathered}[/tex]Final answer
Option C is equivalent to the expression.
