ThisThe sum of angles in a triangle
[tex]=180^0[/tex]
The angles given in the triangle are
[tex]x^0,74,47^0^{}^{}^{}_{}^{}[/tex]
Which means that,
[tex]x^0+47^0+74^0=180^0[/tex][tex]\begin{gathered} x^0+121^0=180^0 \\ \text{collecting like terms,we will have} \\ x^0=180^0-121^0 \\ x^0=59^0 \end{gathered}[/tex]
Hence,
The final answer is x=59°
