Given
Also, CF = FB and AE = EB, CB = 38 and AB = 22.
To find the length of DE.
Explanation:
It is given that,
Also, CF = FB and AE = EB, CB = 38 and AB = 22.
That implies,
By using midpoint theorem of triangle, we have,
[tex]DE=\frac{1}{2}BC[/tex]
Therefore,
[tex]\begin{gathered} DE=\frac{1}{2}\times38 \\ =19 \end{gathered}[/tex]
