Respuesta :

[tex]\begin{gathered} f(x)=2\sin (x-\frac{\pi}{2})-1 \\ Maximum=1 \\ \text{midline}=\frac{1+(-3)}{2}=\frac{1-3}{2}=\frac{-2}{2}=-1 \\ \text{midline}=-1 \\ The\text{ midline is y=-1} \\ \text{Interval = (0,2}\pi\text{)} \end{gathered}[/tex]

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