Given data:
In a right angle triangle hypotenues is given that is
[tex]H=x\sqrt[]{2}[/tex]
Now, by the Pythagorean theorem we have
[tex]\text{Hypotenues}^2=Perpendicular^2+Base^2[/tex]
So, by the hit and trial method
Let , perpendicular = base = x we get
[tex]\begin{gathered} H^{}=\sqrt[]{x^2+x^2} \\ H=\sqrt[]{2x^2} \\ H=x\sqrt[]{2} \end{gathered}[/tex]
Thus, the correct option is (1) that is x
