Given data:
* The time taken by the Adam is,
[tex]\begin{gathered} t=21\text{ min} \\ t=1260\text{ s} \end{gathered}[/tex]* The average velocity of the Adam is,
[tex]\begin{gathered} v=9.98kmh^{-1} \\ v=9.98\times\frac{10^3}{60\times60}ms^{-1} \\ v=2.77ms^{-1} \end{gathered}[/tex]Solution:
The distance traveled by the Adam is,
[tex]\begin{gathered} d=vt \\ d=2.77\times1260 \\ d=3490.2\text{ m} \\ d=3.49\text{ km} \end{gathered}[/tex]Thus, the distance traveled by the Adam on the bicycle is 3.49 km.
