Given:
circumference of 62.8
Required:
circumference of 62.8
Explanation:
Let r be the radius of the circle
Since the circumference of the circle is 62.8
[tex]\begin{gathered} 2\pi r=62.8 \\ \\ 2\times3.14\times r=62.8 \\ \\ 6.28r=62.8 \\ \\ r=\frac{62.8}{6.28} \\ \\ r=10 \end{gathered}[/tex]area of circle is
[tex]\begin{gathered} \pi r^2 \\ \\ 3.14\times10\times10 \\ \\ =314 \end{gathered}[/tex]Required answer:
10, 314
