To find JL
We will first find the value of x
JK = KL
2(x+6) = 3x + 8
2x + 12 = 3x+ 8
subtract 2x from both-side of the equation
12 = 3x-2x + 8
12 = x+ 8
subtract 8 from both-side of the equation
12 - 8 = x+ 8 - 8
4 = x
x=4
JK = 2(x+ 6)
substitute x = 4 into the above
JK = 2(4+6)
JK=2(10)
JK=20
KL =3x+8
substitute x=4 into the above
KL = 3(4) + 8
KL = 12 + 8
KL=20
JL = JK + KL
= 20 + 20
= 40
JL = 40 units
