Solution
We have the following equation:
5(x+3)= 3y+12 (1)
Solving for y we got:
3y= -12+ 5(x+3)
3y = -12 + 5x+15
3y= 5x +3
y= 5/3 x +1
The slope for the first case is: m1= 5/3
5x + 3y = 15 (2)
Solving for y we got:
3y= 15-5x
y= 5 -5/3x
The slope is given by : m2= -5/3
Then m1*m2 is not equal to -1 (NOT perpendicular)
m1 is different from m2 (NOT parallel)
Then are not perpendicular or parallel
